|
| 1 | + |
| 2 | +from typing import Tuple |
| 3 | + |
| 4 | + |
| 5 | +class TrieNode(object): |
| 6 | + """ |
| 7 | + Our trie node implementation. Very basic. but does the job |
| 8 | + """ |
| 9 | + |
| 10 | + def __init__(self, char: str): |
| 11 | + self.char = char |
| 12 | + self.children = [] |
| 13 | + # Is it the last character of the word.` |
| 14 | + self.word_finished = False |
| 15 | + # How many times this character appeared in the addition process |
| 16 | + self.counter = 1 |
| 17 | + |
| 18 | + |
| 19 | +def add(root, word: str): |
| 20 | + """ |
| 21 | + Adding a word in the trie structure |
| 22 | + """ |
| 23 | + node = root |
| 24 | + for char in word: |
| 25 | + found_in_child = False |
| 26 | + # Search for the character in the children of the present `node` |
| 27 | + for child in node.children: |
| 28 | + if child.char == char: |
| 29 | + # We found it, increase the counter by 1 to keep track that another |
| 30 | + # word has it as well |
| 31 | + child.counter += 1 |
| 32 | + # And point the node to the child that contains this char |
| 33 | + node = child |
| 34 | + found_in_child = True |
| 35 | + break |
| 36 | + # We did not find it so add a new chlid |
| 37 | + if not found_in_child: |
| 38 | + new_node = TrieNode(char) |
| 39 | + node.children.append(new_node) |
| 40 | + # And then point node to the new child |
| 41 | + node = new_node |
| 42 | + # Everything finished. Mark it as the end of a word. |
| 43 | + node.word_finished = True |
| 44 | + |
| 45 | + |
| 46 | +def find_prefix(root, prefix: str) -> Tuple[bool, int]: |
| 47 | + """ |
| 48 | + Check and return |
| 49 | + 1. If the prefix exsists in any of the words we added so far |
| 50 | + 2. If yes then how may words actually have the prefix |
| 51 | + """ |
| 52 | + node = root |
| 53 | + # If the root node has no children, then return False. |
| 54 | + # Because it means we are trying to search in an empty trie |
| 55 | + if not root.children: |
| 56 | + return False, 0 |
| 57 | + for char in prefix: |
| 58 | + char_not_found = True |
| 59 | + # Search through all the children of the present `node` |
| 60 | + for child in node.children: |
| 61 | + if child.char == char: |
| 62 | + # We found the char existing in the child. |
| 63 | + char_not_found = False |
| 64 | + # Assign node as the child containing the char and break |
| 65 | + node = child |
| 66 | + break |
| 67 | + # Return False anyway when we did not find a char. |
| 68 | + if char_not_found: |
| 69 | + return False, 0 |
| 70 | + # Well, we are here means we have found the prefix. Return true to indicate that |
| 71 | + # And also the counter of the last node. This indicates how many words have this |
| 72 | + # prefix |
| 73 | + return True, node.counter |
| 74 | + |
| 75 | +if __name__ == "__main__": |
| 76 | + root = TrieNode('*') |
| 77 | + add(root, "hackathon") |
| 78 | + add(root, 'hack') |
| 79 | + |
| 80 | + print(find_prefix(root, 'hac')) |
| 81 | + print(find_prefix(root, 'hack')) |
| 82 | + print(find_prefix(root, 'hackathon')) |
| 83 | + print(find_prefix(root, 'ha')) |
| 84 | + print(find_prefix(root, 'hammer')) |
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