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| 1 | +#include <bits/stdc++.h> |
| 2 | +using namespace std; |
| 3 | + |
| 4 | +double query(vector<vector<double>>& dp,int N,int i,int j,int K){ |
| 5 | + |
| 6 | + if(i<0||i>=N||j<0||j>=N){ |
| 7 | + return 0; |
| 8 | + } |
| 9 | + |
| 10 | + if(dp[N*i+j][K]!=-1){ |
| 11 | + return dp[N*i+j][K]; |
| 12 | + } |
| 13 | + double ans = 0; |
| 14 | + ans+=query(dp,N,i+1,j+2,K-1) |
| 15 | + +query(dp,N,i+1,j-2,K-1) |
| 16 | + +query(dp,N,i-1,j+2,K-1) |
| 17 | + +query(dp,N,i-1,j-2,K-1) |
| 18 | + +query(dp,N,i+2,j+1,K-1) |
| 19 | + +query(dp,N,i+2,j-1,K-1) |
| 20 | + +query(dp,N,i-2,j+1,K-1) |
| 21 | + +query(dp,N,i-2,j-1,K-1); |
| 22 | + |
| 23 | + ans/=8; |
| 24 | + dp[i*N+j][K] = ans; |
| 25 | + return ans; |
| 26 | + |
| 27 | +} |
| 28 | + |
| 29 | +double knightProbability(int N, int K, int r, int c) { |
| 30 | + |
| 31 | + double ans = 0; |
| 32 | + |
| 33 | + vector<vector<double>> dp(625,vector<double>(100)); |
| 34 | + |
| 35 | + for(int i=0;i<N*N;i++){ |
| 36 | + dp[i][0] = 0; |
| 37 | + for(int j=1;j<=K;j++){ |
| 38 | + dp[i][j] = -1; |
| 39 | + } |
| 40 | + } |
| 41 | + |
| 42 | + dp[r*N+c][0] = 1; |
| 43 | + for(int i=0;i<N;i++){ |
| 44 | + for(int j=0;j<N;j++){ |
| 45 | + ans+=query(dp,N,i,j,K); |
| 46 | + } |
| 47 | + } |
| 48 | + |
| 49 | + |
| 50 | + return ans; |
| 51 | +} |
| 52 | + |
| 53 | + |
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