forked from TheAlgorithms/Python
-
Notifications
You must be signed in to change notification settings - Fork 0
/
Copy pathmodular_division.py
150 lines (104 loc) · 3.16 KB
/
modular_division.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
144
145
146
147
148
149
150
# Modular Division :
# An efficient algorithm for dividing b by a modulo n.
# GCD ( Greatest Common Divisor ) or HCF ( Highest Common Factor )
# Given three integers a, b, and n, such that gcd(a,n)=1 and n>1, the algorithm should return an integer x such that
# 0≤x≤n−1, and b/a=x(modn) (that is, b=ax(modn)).
# Theorem:
# a has a multiplicative inverse modulo n iff gcd(a,n) = 1
# This find x = b*a^(-1) mod n
# Uses ExtendedEuclid to find the inverse of a
def modular_division(a, b, n):
"""
>>> modular_division(4,8,5)
2
>>> modular_division(3,8,5)
1
>>> modular_division(4, 11, 5)
4
"""
assert n > 1 and a > 0 and greatest_common_divisor(a, n) == 1
(d, t, s) = extended_gcd(n, a) # Implemented below
x = (b * s) % n
return x
# This function find the inverses of a i.e., a^(-1)
def invert_modulo(a, n):
"""
>>> invert_modulo(2, 5)
3
>>> invert_modulo(8,7)
1
"""
(b, x) = extended_euclid(a, n) # Implemented below
if b < 0:
b = (b % n + n) % n
return b
# ------------------ Finding Modular division using invert_modulo -------------------
# This function used the above inversion of a to find x = (b*a^(-1))mod n
def modular_division2(a, b, n):
"""
>>> modular_division2(4,8,5)
2
>>> modular_division2(3,8,5)
1
>>> modular_division2(4, 11, 5)
4
"""
s = invert_modulo(a, n)
x = (b * s) % n
return x
# Extended Euclid's Algorithm : If d divides a and b and d = a*x + b*y for integers x and y, then d = gcd(a,b)
def extended_gcd(a, b):
"""
>>> extended_gcd(10, 6)
(2, -1, 2)
>>> extended_gcd(7, 5)
(1, -2, 3)
** extended_gcd function is used when d = gcd(a,b) is required in output
"""
assert a >= 0 and b >= 0
if b == 0:
d, x, y = a, 1, 0
else:
(d, p, q) = extended_gcd(b, a % b)
x = q
y = p - q * (a // b)
assert a % d == 0 and b % d == 0
assert d == a * x + b * y
return (d, x, y)
# Extended Euclid
def extended_euclid(a, b):
"""
>>> extended_euclid(10, 6)
(-1, 2)
>>> extended_euclid(7, 5)
(-2, 3)
"""
if b == 0:
return (1, 0)
(x, y) = extended_euclid(b, a % b)
k = a // b
return (y, x - k * y)
# Euclid's Lemma : d divides a and b, if and only if d divides a-b and b
# Euclid's Algorithm
def greatest_common_divisor(a, b):
"""
>>> greatest_common_divisor(7,5)
1
Note : In number theory, two integers a and b are said to be relatively prime, mutually prime, or co-prime
if the only positive integer (factor) that divides both of them is 1 i.e., gcd(a,b) = 1.
>>> greatest_common_divisor(121, 11)
11
"""
if a < b:
a, b = b, a
while a % b != 0:
a, b = b, a % b
return b
if __name__ == "__main__":
from doctest import testmod
testmod(name="modular_division", verbose=True)
testmod(name="modular_division2", verbose=True)
testmod(name="invert_modulo", verbose=True)
testmod(name="extended_gcd", verbose=True)
testmod(name="extended_euclid", verbose=True)
testmod(name="greatest_common_divisor", verbose=True)