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0695-max-area-of-island.cpp
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0695-max-area-of-island.cpp
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/*
Given grid where '1' is land & '0' is water, return largest island
DFS, set visited land to '0' to not visit it again, store biggest
Time: O(m x n)
Space: O(m x n)
*/
class Solution {
public:
int maxAreaOfIsland(vector<vector<int>>& grid) {
int m = grid.size();
int n = grid[0].size();
int result = 0;
for (int i = 0; i < m; i++) {
for (int j = 0; j < n; j++) {
if (grid[i][j] == 1) {
result = max(result, dfs(grid, i, j, m, n));
}
}
}
return result;
}
private:
int dfs(vector<vector<int>>& grid, int i, int j, int m, int n) {
if (i < 0 || i >= m || j < 0 || j >= n || grid[i][j] == 0) {
return 0;
}
grid[i][j] = 0;
return 1 + dfs(grid, i - 1, j, m, n) + dfs(grid, i + 1, j, m, n)
+ dfs(grid, i, j - 1, m, n) + dfs(grid, i, j + 1, m, n);
}
};