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Linked List Cycle

Description

link


Solution


Code

T : O(m + n) S : O(1)

# Definition for singly-linked list.
# class ListNode(object):
#     def __init__(self, x):
#         self.val = x
#         self.next = None

class Solution(object):
    def hasCycle(self, head):
        """
        :type head: ListNode
        :rtype: bool
        """
        try:
            slow = head
            fast = head.next
            while slow is not fast:
                slow = slow.next
                fast = fast.next.next
            return True
        except:
            return False