Parse Json Response

[nirvine]

I would like to get the temperature from a Sensibo smart air conditioning device, but cannot seem to work out the structure of the json parse statement. I have used the following in the On Success section:

const temperature = JSON.parse(response.body).result.temperature;
setVariable('temperature',temperature);
showDialog('Indoor Temp: '+temperature+' °C', 'Temperature');

The json data is:
{"status": "success", "result": [{"time": {"time": "2021-10-09T08:41:20.666359Z", "secondsAgo": 71}, "temperature": 23.3, "humidity": 60.7, "feelsLike": 23.3, "rssi": -58, "motion": false, "roomIsOccupied": true}]}

Output is "Indoor Temp: undefined C"

What have I done wrong?
And the next step would be to include the humidity in the output, but temperature is more important to me.

"

[Waboodoo]

Change the first line to the following:

const temperature = JSON.parse(response.body).result[0].temperature;

"result" is an array with one element, so you need to select the 0-th element from it before you try to access temperature.
The same should work for accessing the humidity:

const result = JSON.parse(response.body).result[0];
const temperature = result.temperature;
const humidity = result.humidity;

Also, you probably don't need the second line of your code (where you call setVariable), unless you actual have a global variable called "temperature" set up in the app which you are using somewhere else in the same shortcut (e.g. in a header) or in some other place. If you only need the temperature value right inside the JS code then a JS variable is enough and you don't need to go with getVariable() and setVariable().

[nirvine]

Many thanks - it is working now. I could not find a guide on the format of the parse statement.

[Waboodoo]

You can find more information about JSON.parse() here for example: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/JSON/parse