incorrect answer to regex practice problem hpa-day-p1

[bnmnetp]

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This is the first of the advanced microparsons practice problems for regex.
\d{2}/\d{2}/(\d{2}|\d{4}) should be \d{2}/\d{2}/(\d{4}|\d{2})

If the longer \d{4} is not first then it will always match with the \d{2} and will return the first two digits of the year for example 20 of 2025 if the full four digit year is provided.

In [1]: import re

In [2]: re.match(r'\d{2}/\d{2}/(\d{2}|\d{4})', '12/22/2024')
Out[2]: <re.Match object; span=(0, 8), match='12/22/20'>

In [3]: re.match(r'\d{2}/\d{2}/(\d{2}|\d{4})', '12/22/24')
Out[3]: <re.Match object; span=(0, 8), match='12/22/24'>

In [4]: re.match(r'\d{2}/\d{2}/(\d{4}|\d{2})', '12/22/24')
Out[4]: <re.Match object; span=(0, 8), match='12/22/24'>

In [5]: re.match(r'\d{2}/\d{2}/(\d{4}|\d{2})', '12/22/2024')
Out[5]: <re.Match object; span=(0, 10), match='12/22/2024'>

In [6]: re.match(r'\d{2}/\d{2}/(\d{2}|\d{4})', '12/22/2024').groups()
Out[6]: ('20',)