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code/lc142.java

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* 题意:求链表环的起始节点
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* 难度:Medium
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* 分类:Linked List, Two Pointers
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* 思路:lc141进一步问题。快慢指针相遇后走了a+b步,head 走a步后到起始点,则 a+b+n=2a+2b -> a+b=n 所以相遇点再走a步到起始点。相遇以后再设一个指针从head开始走,满指针接着走,则相遇点为环的入口点。
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* 思路:lc141进一步问题。快慢指针相遇后走了a+b步,head 走a步后到起始点,则 a+b+n=2a+2b -> a+b=n 所以相遇点再走a步到起始点。相遇以后再设一个指针从head开始走,慢指针接着走,则相遇点为环的入口点。
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* Tips:
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*/
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public class lc142 {

readme.md

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| 162 [Java](./code/lc162.java)
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| 166 [Java](./code/lc166.java)
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| 169 [Java](./code/lc169.java)
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| 171 [Java](./code/lc171.java)
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| 172 [Java](./code/lc172.java)
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| 179 [Java](./code/lc179.java)
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| 189 [Java](./code/lc189.java)
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| 198 [Java](./code/lc198.java)
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| 200 [Java](./code/lc200.java)
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| 206 [Java](./code/lc206.java)
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| 207 [Java](./code/lc207.java)
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| 208 [Java](./code/lc208.java)
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| 210 [Java](./code/lc210.java)
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| 212 [Java](./code/lc212.java)
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| 215 [Java](./code/lc215.java)
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| 221 [Java](./code/lc221.java)

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