forked from gouthampradhan/leetcode
-
Notifications
You must be signed in to change notification settings - Fork 0
/
Copy pathLCA.java
45 lines (41 loc) · 1.36 KB
/
LCA.java
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
package tree;
/**
* Created by gouthamvidyapradhan on 21/03/2017. Given a binary tree, find the lowest common
* ancestor (LCA) of two given nodes in the tree.
*
* <p>According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined
* between two nodes v and w as the lowest node in T that has both v and w as descendants (where we
* allow a node to be a descendant of itself).”
*
* <p>_______3______ / \ ___5__ ___1__ / \ / \ 6 _2 0 8 / \ 7 4 For example, the lowest common
* ancestor (LCA) of nodes 5 and 1 is 3. Another example is LCA of nodes 5 and 4 is 5, since a node
* can be a descendant of itself according to the LCA definition.
*/
public class LCA {
public class TreeNode {
int val;
TreeNode left;
TreeNode right;
TreeNode(int x) {
val = x;
}
}
/**
* Main method
*
* @param args
* @throws Exception
*/
public static void main(String[] args) throws Exception {}
public TreeNode lowestCommonAncestor(TreeNode root, TreeNode p, TreeNode q) {
if (root != null) {
if (root.equals(p) || root.equals(q)) return root;
TreeNode left = lowestCommonAncestor(root.left, p, q);
TreeNode right = lowestCommonAncestor(root.right, p, q);
if (left != null && right != null) return root;
else if (left != null) return left;
else return right;
}
return null;
}
}