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How to understand "The variance of the conical frustum with respect to its radius r is equal to the variance of the frustum with respect to x or (by symmetry) y. "
#44
How to understand "The variance of the conical frustum with respect to its radius r is equal to the variance of the frustum with respect to x or (by symmetry) y. "in Supplemental Material?
I think
Var(r)=E(r^2)-E(r)^2 where -R<r<R so E(r)=0
E(r^2)=E(x^2+y^2)=E(x^2)+E(y^2)=E(x^2)-E(x)^2+E(y^2)-E(y)^2=Var(x)+Var(y) where E(x)=0 E(y)=0
SO Var(r)=Var(x)+Var(y) rather than Var(r)=Var(x)
Where is my mistake?
The text was updated successfully, but these errors were encountered:
Hi everyone, thanks for helping investigate this! It seems like there's almost certainly a bug in the math where I missed a 2x multiplier. My mistake, sorry! This explains a lot, as we've noticed other places in the math where we seem to be wrong by a factor of two. I will dig into this and attempt to fix it --- though if anyone else wants to patch the math and push a CL with updated unit tests, feel free!
I don't know if this improvement will improve the effect? The fitting ability of neural networks is too strong, may a difference of two times not affect the results too much? Look forward to your reply!
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How to understand "The variance of the conical frustum with respect to its radius r is equal to the variance of the frustum with respect to x or (by symmetry) y. "in Supplemental Material?
I think
Var(r)=E(r^2)-E(r)^2 where -R<r<R so E(r)=0
E(r^2)=E(x^2+y^2)=E(x^2)+E(y^2)=E(x^2)-E(x)^2+E(y^2)-E(y)^2=Var(x)+Var(y) where E(x)=0 E(y)=0
SO Var(r)=Var(x)+Var(y) rather than Var(r)=Var(x)
Where is my mistake?
The text was updated successfully, but these errors were encountered: