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hashtable/0383 Ransom Note.md

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# 383. Ransom Note
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https://leetcode-cn.com/problems/ransom-note/
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Given two strings ransomNote and magazine, return true if ransomNote can be constructed from magazine and false otherwise.
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Each letter in magazine can only be used once in ransomNote.
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Example 1:
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Input: ransomNote = "a", magazine = "b"
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Output: false
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Example 2:
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Input: ransomNote = "aa", magazine = "ab"
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Output: false
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Example 3:
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Input: ransomNote = "aa", magazine = "aab"
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Output: true
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Constraints:
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1 <= ransomNote.length, magazine.length <= 10^5
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ransomNote and magazine consist of lowercase English letters.
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## hashtable
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``` python3
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class Solution:
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def canConstruct(self, ransomNote: str, magazine: str) -> bool:
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note_dict=Counter(ransomNote)
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maga_dict=Counter(magazine)
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for k,v in note_dict.items():
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if k not in maga_dict.keys() or maga_dict[k]<v:
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return False
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return True
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```
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## bucket
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``` python3
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class Solution:
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def canConstruct(self, ransomNote: str, magazine: str) -> bool:
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note_dict=defaultdict(int)
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for i in ransomNote:
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note_dict[i]+=1
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maga_dict=defaultdict(int)
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for i in magazine:
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maga_dict[i]+=1
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for i in ransomNote:
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if i not in maga_dict or note_dict[i]>maga_dict[i]:
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return False
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return True
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```
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