local

Author: mostafa-saad

18-Programming-4kids/06_homework_01_answer.cpp

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+#include<iostream>
+using namespace std;
+
+int main() {
+
+	int num;
+	cin >> num;
+
+	// Is even using %2
+	bool is_even1 = (num % 2 == 0);
+
+	// is even using /2
+	double by2 = (double) num / 2.0;// this is either X.0 or X.5  (try 10, 11)
+	by2 = by2 - (int) by2;// Remove X. This is now either 0 (for even) or 0.5 (for odd)
+	bool is_even2 = by2 == 0;
+
+	// is even using %2
+	int last_digit = num % 10;	// even last digit is 0, 2, 4, 6, 8
+	bool is_even3 = last_digit == 0 || last_digit == 2 || last_digit == 4 || last_digit == 6 || last_digit == 8;
+
+	return 0;
+}
+

18-Programming-4kids/06_homework_02_answer.cpp

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+#include<iostream>
+using namespace std;
+
+int main() {
+
+	double a1, a2, a3, a4, a5;
+	cin >> a1 >> a2 >> a3 >> a4 >> a5;
+
+	double avg1 = (a1+a2+a3+a4+a5) / 5.0;	// A
+	double sum1 = (a1+a2+a3) / (a4+a5);		// B
+	double first3_avg = (a1+a2+a3) / 3.0;
+	double last2_avg = (a4+a5) / 2.0;
+	double avg2 = first3_avg / last2_avg;	// C
+
+	cout<<avg1<<"\n";
+	cout<<sum1<<"\n";
+	cout<<avg2<<"\n";
+
+	cout<<sum1 * 2.0/3.0<<"\n";		// C = 2/3 B
+
+	return 0;
+}
+

18-Programming-4kids/06_homework_03_answer.cpp

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+#include<iostream>
+using namespace std;
+
+int main() {
+
+	int n;
+	cin >> n;
+
+	int last1 = n % 10;
+	n /= 10;
+
+	int last2 = n % 10;
+	n /= 10;
+
+	int last3 = n % 10;
+	n /= 10;
+
+	cout << last1 + last2 + last3 << "\n";
+
+	return 0;
+}
+

18-Programming-4kids/06_homework_04_answer.cpp

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+#include<iostream>
+using namespace std;
+
+int main() {
+
+	int n;
+	cin >> n;
+
+	// /1000 => removes last 3 digits
+	// %10 get next digit = 4th
+	cout << (n / 1000) % 10 << "\n";
+
+	return 0;
+}
+

18-Programming-4kids/06_homework_05_answer.cpp

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+#include<iostream>
+using namespace std;
+
+int main() {
+
+	double a, b;
+	cin>>a>>b;
+
+	double result = a/b;
+
+	cout<<result - (int)result;
+
+	return 0;
+}
+

18-Programming-4kids/06_homework_06_answer.cpp

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+#include<iostream>
+using namespace std;
+
+int main() {
+
+	int n, m;
+	cin >> n >> m;
+
+	// let's try 13/5
+	// 13/5 = 2  [2 complete units, each is 5]
+	// 2*5 = 10  [total complete units]
+	// Reminder is 13-10 = 3. This number generates the fractional part
+	int result = n - (n / m) * m;
+
+	cout << result << " " << n % m << "\n";
+
+	return 0;
+}
+

18-Programming-4kids/06_homework_07_answer.cpp

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+#include<iostream>
+using namespace std;
+
+int main() {
+
+	int n;
+	cin >> n;
+
+	int is_even = n % 2 == 0;
+	int is_odd = 1 - is_even;
+
+	// formula of 2 parts: only one of them will be activated
+	int result = is_even * 100 + is_odd * 7;
+
+	cout<<result<<"\n";
+
+
+
+	return 0;
+}
+