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1202.cpp
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#include <bits/stdc++.h>
using namespace std;
#define print_op(...) ostream& operator<<(ostream& out, const __VA_ARGS__& u)
template<typename A, typename B> print_op(pair<A, B>) { return out << "(" << u.first << ", " << u.second << ")"; }
template<typename T_container, typename T = typename enable_if<!is_same<T_container, string>::value, typename T_container::value_type>::type> print_op(T_container) { out << "{"; string sep; for (const T &x : u) out << sep << x, sep = ", "; return out << "}"; }
template<typename T> void dbg_out(string s, T x) {cerr << "\033[1;35m" << s << "\033[0;32m = \033[33m" << x << "\033[0m\n";}
template<typename T, typename... Args> void dbg_out(string s, T x, Args... args) {for (int i=0, b=0; i<(int)s.size(); i++) if (s[i] == '(' || s[i] == '{') b++; else
if (s[i] == ')' || s[i] == '}') b--; else if (s[i] == ',' && b == 0) {cerr << "\033[1;35m" << s.substr(0, i) << "\033[0;32m = \033[33m" << x << "\033[31m | "; dbg_out(s.substr(s.find_first_not_of(' ', i + 1)), args...); break;}}
#ifdef LOCAL
#define dbg(...) dbg_out(#__VA_ARGS__, __VA_ARGS__)
#else
#define dbg(...)
#endif
#define ar array
#define ll long long
#define ld long double
#define sz(x) ((int)x.size())
#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)
#define all(a) (a).begin(), (a).end()
const int MAX_N = 1e5 + 5;
const int MAX_L = 20;
const int MAX_C = 26;
const ll MOD = 1e9 + 7;
const ll INF = 1e9;
const ld EPS = 1e-9;
int n, m;
vector<ar<int,2>> adj[MAX_N];
ll dist[MAX_N];
int cnt[MAX_N], mn[MAX_N], mx[MAX_N];
void dijkstra(int s) {
memset(dist, 0x3f, sizeof dist);
priority_queue<ar<ll,2>,vector<ar<ll,2>>,greater<ar<ll,2>>> pq;
pq.push({dist[s] = 0, s});
cnt[0] = 1;
while (!pq.empty()) {
auto [d, u] = pq.top(); pq.pop();
if (d > dist[u]) continue;
for (auto [v, w] : adj[u]) {
if (dist[v] > dist[u] + w) {
dist[v] = dist[u] + w;
pq.push({dist[v], v});
cnt[v] = cnt[u];
mn[v] = mn[u] + 1;
mx[v] = mx[u] + 1;
} else if (dist[v] == dist[u] + w) {
cnt[v] += cnt[u];
if (cnt[v] >= MOD) cnt[v] -= MOD;
mn[v] = min(mn[v], mn[u] + 1);
mx[v] = max(mx[v], mx[u] + 1);
}
}
}
}
void solve(int tc = 0) {
cin >> n >> m;
for (int i = 0; i < m; i++) {
int u, v, w; cin >> u >> v >> w; u--; v--;
adj[u].push_back({v, w});
}
dijkstra(0);
cout << dist[n - 1] << " " << cnt[n - 1] << " " << mn[n - 1] << " " << mx[n - 1] << "\n";
}
signed main() {
ios_base::sync_with_stdio(false); cin.tie(NULL);
int tc = 1;
// cin >> tc;
for (int t = 1; t <= tc; t++) {
// cout << "Case #" << t << ": ";
solve(t);
}
}