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| 1 | +#define ALLOCATION_SIZE 100 // Allocation size of the numsArrLen in frequencyArrItem |
| 2 | + |
| 3 | +typedef struct hash_entry { |
| 4 | + int num; /* we'll use this field as the key */ |
| 5 | + int count; |
| 6 | + UT_hash_handle hh; /* makes this structure hashable */ |
| 7 | +}hash_entry; |
| 8 | + |
| 9 | +typedef struct frequencyArrItem |
| 10 | +{ |
| 11 | + int* numsArr; |
| 12 | + int numsArrLen; |
| 13 | + int index; // Points to the first empty space in numsArr |
| 14 | +}frequencyArrItem; |
| 15 | + |
| 16 | +/** |
| 17 | + * Note: The returned array must be malloced, assume caller calls free(). |
| 18 | + */ |
| 19 | +int* topKFrequent(int* nums, int numsSize, int k, int* returnSize){ |
| 20 | + int* result = (int*)malloc(k * sizeof(int)); |
| 21 | + *returnSize = k; |
| 22 | + int resultIndex = 0; // Points to the first empty space in result |
| 23 | + hash_entry* NumFreqMap = NULL; |
| 24 | + frequencyArrItem frequencyArr[numsSize + 1]; // Index is the count/frequency and the element is an array of numbers with this frequency |
| 25 | + memset(frequencyArr, 0, (numsSize + 1) * sizeof(frequencyArrItem)); // Initialize with NULL and zeros |
| 26 | + |
| 27 | + for(int i = 0; i < numsSize; i++) |
| 28 | + { |
| 29 | + hash_entry* retrievedMapEntry; |
| 30 | + HASH_FIND_INT(NumFreqMap, &nums[i], retrievedMapEntry); |
| 31 | + |
| 32 | + // If the number already exists in the map then increment its count |
| 33 | + if(retrievedMapEntry) |
| 34 | + { |
| 35 | + retrievedMapEntry->count += 1; |
| 36 | + } |
| 37 | + else |
| 38 | + { |
| 39 | + // If the number doesn't exist in the map then create a new map entry for it and add it to the map |
| 40 | + hash_entry* mapEntryToAdd = (hash_entry*)malloc(sizeof(hash_entry)); |
| 41 | + mapEntryToAdd->num = nums[i]; |
| 42 | + mapEntryToAdd->count = 1; |
| 43 | + HASH_ADD_INT(NumFreqMap, num, mapEntryToAdd); |
| 44 | + } |
| 45 | + } |
| 46 | + |
| 47 | + // Loop over all the entries in the hash map |
| 48 | + for (hash_entry* mapEntry = NumFreqMap; mapEntry != NULL; mapEntry = mapEntry->hh.next) { |
| 49 | + frequencyArrItem* freq = frequencyArr + mapEntry->count; |
| 50 | + |
| 51 | + // If the nums list for this frequency has not been created yet |
| 52 | + if(freq->numsArrLen == 0) |
| 53 | + { |
| 54 | + freq->numsArrLen = ALLOCATION_SIZE; |
| 55 | + freq->numsArr = (int*)malloc(freq->numsArrLen * sizeof(int)); |
| 56 | + } |
| 57 | + // If the nums list exceeded the current allocated size, then reallocate |
| 58 | + else if(freq->index == freq->numsArrLen) |
| 59 | + { |
| 60 | + freq->numsArrLen += ALLOCATION_SIZE; |
| 61 | + freq->numsArr = (int*)realloc(freq->numsArr, freq->numsArrLen * sizeof(int)); |
| 62 | + } |
| 63 | + |
| 64 | + freq->numsArr[freq->index++] = mapEntry->num; |
| 65 | + } |
| 66 | + |
| 67 | + // Loop over the frequencies starting from the highest frequency |
| 68 | + for(int i = numsSize; i >= 1; i--) // Note that we are looping until i == 1, as at index 0 it is just empty |
| 69 | + { |
| 70 | + frequencyArrItem* freq = frequencyArr + i; |
| 71 | + // If there is nums that exist at this particular frequency |
| 72 | + for(int j = 0; j < freq->index; j++) |
| 73 | + { |
| 74 | + // If we have added all the elements we need to the result |
| 75 | + if(k-- == 0) |
| 76 | + { |
| 77 | + return result; |
| 78 | + } |
| 79 | + |
| 80 | + // Add the num to the result then increment the index |
| 81 | + result[resultIndex++] = freq->numsArr[j]; |
| 82 | + } |
| 83 | + } |
| 84 | + |
| 85 | + return result; |
| 86 | +} |
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