Close/leave room

[veezeepee]

If I use the 'basic' SimpleWebRTC example I cannot work out how to 'leave/disconnect' from a room. My 'needs' are actually very simple the room is actually the page automatically e.g. the page has an automatic session variable rather than page.html#abc or page.html?id=abc - so from what I see/understand (newbie here ;)) (and to suit my purposes) the 'basic' code should surfice, however, I don't want the video to auto start and or auto request permission. I want that from a button 'Start Video' - get that to work, but then I cannot close/leave the room. (p.s. not very good with JS) - simple code: looks like (know cannot) what I cannot do is access webrtc inside closeVideo, but cannot fathom a way to get webrtc from startVideo() to closeVideo()

HTML
Start Video
Stop Video

JS

function startVideo(){
var webrtc = new SimpleWebRTC({
localVideoEl: 'localVideo',
remoteVideosEl: 'remoteVideos',
autoRequestMedia: false
});
webrtc.once('readyToCall', function () {
webrtc.joinRoom('your awesome room name');
});
}

function closeVideo(){
webrtc.connection.disconnect();
}

[devdemi]

try webrtc.leaveRoom();

[nsarkar]

webrtc.leaveRoom() just disconnects the remote video. Is there a way to stop the localVideoStream. It seems like leaveRoom should do it but the code that calls stopScreenShare doesn't work. Any suggestions?
I see we have an issue where someone fixed this - #4.
Will try that.

[foligno]

I'm currently using the following code to achieve that.

function hangUp() {
  webrtc.stopLocalVideo();
  webrtc.leaveRoom();
}

[namnemet]

how can i make a specific viewer to leave a room ?
or
perhaps shut down his ability to view the room? (if this is easier)