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Update 0014-longest-common-prefix.cpp
The existing solution was for four sum, I replaced with the actual problem solution Submission URL: https://leetcode.com/problems/longest-common-prefix/submissions/867645947/
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Original file line number | Diff line number | Diff line change |
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@@ -1,59 +1,28 @@ | ||
class Solution { | ||
public: | ||
vector<vector<int>> res; | ||
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vector<vector<int>> fourSum(vector<int>& nums, int target) { | ||
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if(nums.size() < 4) return res; | ||
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vector<int>quad; | ||
sort(nums.begin() , nums.end()); | ||
kSum(0,4,target,nums,quad); | ||
return res; | ||
} | ||
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void kSum (int index , int k , long long target, vector<int> nums , vector<int>&q) | ||
{ | ||
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if(k == 2) | ||
{ | ||
twoSum(index , target, q , nums); | ||
return; | ||
} | ||
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for(int i = index ; i < nums.size() - k + 1; i++) | ||
{ | ||
if(i > index && nums[i] == nums[i-1]) continue; | ||
q.push_back(nums[i]); | ||
kSum(i+1 , k-1 , target-nums[i] , nums , q); | ||
q.pop_back(); | ||
} | ||
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} | ||
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void twoSum (int start,long long target,vector<int>&ans,vector<int>& nums) | ||
{ | ||
int lo = start; | ||
int hi = nums.size()-1; | ||
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while(lo < hi) | ||
{ | ||
int sum = nums[lo]+nums[hi]; | ||
if(sum > target) hi--; | ||
else if (sum < target) lo++; | ||
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else | ||
{ | ||
ans.insert(ans.end() , {nums[lo] , nums[hi]}); | ||
res.push_back(ans); | ||
string longestCommonPrefix(vector<string>& strs) { | ||
string result = strs[0]; | ||
int charIndex = 0; | ||
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ans.pop_back(); | ||
ans.pop_back(); | ||
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lo++; | ||
while (lo < hi && nums[lo] == nums[lo - 1]) lo++; | ||
} | ||
} | ||
} | ||
//finding minimum string length - that could be max common prefix | ||
long maxCharIndex = strs[0].length(); | ||
for (int i = 1; i < strs.size(); ++i) { | ||
if (strs[i].length() < maxCharIndex) { | ||
maxCharIndex = strs[i].length(); | ||
} | ||
} | ||
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while (charIndex < maxCharIndex) { | ||
char prevChar = strs[0][charIndex]; | ||
for (int i = 1; i < strs.size(); ++i) { | ||
if (prevChar == strs[i][charIndex]) { | ||
continue; | ||
} | ||
return result.substr(0, charIndex); | ||
} | ||
++charIndex; | ||
result += prevChar; | ||
} | ||
return result.substr(0, charIndex); | ||
} | ||
}; |