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//k번 노드에서 가장 멀리 떨어진 노드의 갯수 구하기 | ||
//가장 멀리 떨어진 노드란 최단경로로 이동했을 때 간선의 개수가 가장 많은 노드들을 의미 | ||
//노드의 개수 n: 2 이상 20,000 이하 | ||
//edge는 양방향, 1개 이상 50,000개 이하 | ||
//예시: 노드 간 edge에 대한 vector:[[3, 6], [4, 3], [3, 2], [1, 3], [1, 2], [2, 4], [5, 2]]가 입력으로 들어감 | ||
//bfs 이용 | ||
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#include <string> | ||
#include <vector> | ||
#include <queue> | ||
#include <iostream> | ||
#include <algorithm> | ||
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using namespace std; | ||
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// make class about bfs | ||
class graph{ | ||
public: | ||
int node[20000]; | ||
vector<int> v[50000]; | ||
int max_node; | ||
int node_num; | ||
void count_node(vector<vector<int>>); | ||
void bfs(int); | ||
}; | ||
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void graph::count_node(vector<vector<int>> edge){ | ||
vector<int> unique_vec; | ||
for(int i=0;i<edge.size();++i){ | ||
for(int j=0;j<edge[i].size();++j){ | ||
unique_vec.push_back(edge[i][j]); | ||
} | ||
} | ||
sort(unique_vec.begin(), unique_vec.end()); | ||
unique_vec.erase(unique(unique_vec.begin(), unique_vec.end()), unique_vec.end()); | ||
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node_num = unique_vec.size(); | ||
cout << "node_num: " << node_num << "\n"; | ||
} | ||
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void graph::bfs(int node_n){ | ||
queue<int> q; | ||
q.push(node_n); | ||
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while (!q.empty()){ | ||
int cur = q.front(); | ||
q.pop(); | ||
for (int i=0; i<v[cur].size(); i++){ | ||
if((node[v[cur][i]]==0)&&(v[cur][i]!=1)){ | ||
node[v[cur][i]] = node[cur] + 1; | ||
q.push(v[cur][i]); | ||
max_node = max(max_node, node[v[cur][i]]); | ||
} | ||
} | ||
} | ||
cout << "bfs completed\n"; | ||
} | ||
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int main(){ | ||
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graph g; | ||
char ch; | ||
vector<int> input; | ||
vector<vector<int>> input_vector; | ||
int k; | ||
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cout << "Please enter the vector - example: if [3, 6], enter 3 then 6(enter between vectors) next-> [4, 3]...\n if you want to end, type #\n"; | ||
cin >> ch; | ||
int t = 0; | ||
while(ch !='#'){ | ||
int x = ch - '0'; | ||
cin >> ch; | ||
input.push_back(x); | ||
if(t%2==1){ | ||
input_vector.push_back(input); | ||
vector<int>().swap(input); | ||
} | ||
t++; | ||
} | ||
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for (int i=0; i<input_vector.size(); i++){ | ||
for (int j=0; j<input_vector[i].size(); j++){ | ||
cout << input_vector[i][j] << "; "; | ||
} | ||
} | ||
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cout << "input vector's size is: " << input_vector.size() << "\n"; | ||
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for(int i=0; i<input_vector.size();i++){ | ||
g.v[input_vector[i][0]].push_back(input_vector[i][1]); | ||
g.v[input_vector[i][1]].push_back(input_vector[i][0]); | ||
} | ||
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cout << "Please enter the number of node that you want to search - example: 3\n"; | ||
cin >> k; | ||
g.bfs(k); | ||
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int answer = 0; | ||
g.count_node(input_vector); | ||
for(int i=1; i<=g.node_num;i++){ | ||
if(g.max_node==g.node[i]) | ||
answer++; | ||
} | ||
cout << "node's number is : " << sizeof g.node << "\n"; | ||
cout << "answer is :" << answer; | ||
return answer; | ||
} |