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Create Minimum Cost to Merge Stones.cpp
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//recursion | ||
class Solution { | ||
public: | ||
int recurr(int i,int j,int k,vector<int> &prefix,vector<int> &stones){ | ||
if(j-i<=k-2) return 0; | ||
int mini = INT_MAX; | ||
for(int t=i;t<j;t+=(k-1)){ | ||
int left = recurr(i,t,k,prefix,stones); | ||
int right = recurr(t+1,j,k,prefix,stones); | ||
mini = min(mini,(left+right)); | ||
} | ||
if((j-i)%(k-1)==0){ | ||
int sum=0; | ||
sum+=prefix[j]; | ||
if(i>0){ | ||
sum-=prefix[i-1]; | ||
} | ||
mini+=sum; | ||
} | ||
return mini; | ||
} | ||
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int mergeStones(vector<int>& stones, int k) { | ||
int n = stones.size(); | ||
if((n-1)%(k-1)) return -1; | ||
vector<int> prefix(n,0); | ||
prefix[0] = stones[0]; | ||
for(int i=1;i<n;i++){ | ||
prefix[i] = prefix[i-1]+stones[i]; | ||
} | ||
return recurr(0,n-1,k,prefix,stones); | ||
} | ||
}; | ||
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//memoization | ||
class Solution { | ||
public: | ||
int recurr(int i,int j,int k,vector<int> &prefix,vector<int> &stones,vector<vector<int>> &dp){ | ||
if(j-i<=k-2) return 0; | ||
int mini = INT_MAX; | ||
if(dp[i][j]!=-1) return dp[i][j]; | ||
for(int t=i;t<j;t+=(k-1)){ | ||
int left = recurr(i,t,k,prefix,stones,dp); | ||
int right = recurr(t+1,j,k,prefix,stones,dp); | ||
mini = min(mini,(left+right)); | ||
} | ||
if((j-i)%(k-1)==0){ | ||
int sum=0; | ||
sum+=prefix[j]; | ||
if(i>0){ | ||
sum-=prefix[i-1]; | ||
} | ||
mini+=sum; | ||
} | ||
return dp[i][j]=mini; | ||
} | ||
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int mergeStones(vector<int>& stones, int k) { | ||
int n = stones.size(); | ||
if((n-1)%(k-1)) return -1; | ||
vector<int> prefix(n,0); | ||
prefix[0] = stones[0]; | ||
for(int i=1;i<n;i++){ | ||
prefix[i] = prefix[i-1]+stones[i]; | ||
} | ||
vector<vector<int>> dp(n,vector<int>(n,-1)); | ||
return recurr(0,n-1,k,prefix,stones,dp); | ||
} | ||
}; |