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legend figure 6.8
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emjosephs committed May 7, 2020
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Expand Up @@ -355,12 +355,12 @@ \section{Incomplete Lineage Sorting}
\end{figure}
%JRI: here and in text you refer to populations ABCD but figure is labelled ``species'' and 1234. I think ABCD for populations and AB for alleles is confusing. I don't know if you need A/B for alleles. Why not use A1A2 or just 1/2 as you have previously? sure you miss the fun mnemonic, but it's clearer for a novice reader

Take a look at Figure \ref{fig:ABBA_BABA}. In both cases the lineages from A and B fail to coalesce in
Take a look at Figure \ref{fig:ABBA_BABA}. In both cases the lineages from 1 and 2 fail to coalesce in
their initial shared ancestral population, and one or the other of them
coalesces with the lineage from C before they coalesce with each other. Each option is equally
coalesces with the lineage from 3 before they coalesce with each other. Each option is equally
likely; therefore the mutational patterns ABBA and BABA are equally likely to occur under ILS. \sidenote{Here we have to assume no structure in the ancestral population.}

However, if gene flow occurs from population C into population B, in addition to ILS the lineage from B can more recently coalesce with the lineage from C, and so we should see more ABBAs than BABAs. To test for this effect of gene flow, we can sample a sequence from each of our 4 populations and count up the number of sites that show the two mutational patterns consistent with the gene-tree discordance $n_{ABBA}$ and
However, if gene flow occurs from population 3 into population 2, in addition to ILS the lineage from 2 can more recently coalesce with the lineage from 3, and so we should see more ABBAs than BABAs. To test for this effect of gene flow, we can sample a sequence from each of our 4 populations and count up the number of sites that show the two mutational patterns consistent with the gene-tree discordance $n_{ABBA}$ and
$n_{BABA}$ and calculate
\begin{equation}
\frac{n_{ABBA}-n_{BABA}}{n_{ABBA}+n_{BABA}}
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