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/** | ||
* Definition for singly-linked list. | ||
* struct ListNode { | ||
* int val; | ||
* ListNode *next; | ||
* ListNode() : val(0), next(nullptr) {} | ||
* ListNode(int x) : val(x), next(nullptr) {} | ||
* ListNode(int x, ListNode *next) : val(x), next(next) {} | ||
* }; | ||
*/ | ||
class Solution { | ||
private: | ||
// find middle of LL using slow and fast pointers | ||
ListNode* findLLMid(ListNode* head) { | ||
ListNode* slow = head; | ||
ListNode* fast = head->next; | ||
while (fast != NULL && fast->next != NULL) { | ||
slow = slow->next; | ||
fast = fast->next->next; | ||
} | ||
return slow; | ||
} | ||
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// merges two sorted LLs | ||
ListNode* merge(ListNode* head1, ListNode* head2) { | ||
ListNode* dummy = new ListNode(); | ||
ListNode* p = dummy; | ||
ListNode* p1 = head1; | ||
ListNode* p2 = head2; | ||
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while (p1 != NULL && p2 != NULL) { | ||
if (p1->val < p2->val) { | ||
ListNode* temp = p1->next; | ||
p->next = p1; | ||
p1->next = NULL; | ||
p1 = temp; | ||
} else { | ||
ListNode* temp = p2->next; | ||
p->next = p2; | ||
p2->next = NULL; | ||
p2 = temp; | ||
} | ||
p = p->next; | ||
} | ||
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if (p1 == NULL) { | ||
p->next = p2; | ||
} else if (p2 == NULL) { | ||
p->next = p1; | ||
} | ||
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return dummy->next; | ||
} | ||
public: | ||
// merge sort implementation | ||
ListNode* sortList(ListNode* head) { | ||
// base cases | ||
if (head == NULL) | ||
return NULL; | ||
if (head->next == NULL) | ||
return head; | ||
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// split LL into two halves | ||
ListNode* middleOfLL = findLLMid(head); | ||
ListNode* leftHalf = head; | ||
ListNode* rightHalf = middleOfLL->next; | ||
middleOfLL->next = NULL; // this cuts off the right half from the left half | ||
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// sort the two halves seperately and then merge them into one | ||
leftHalf = sortList(leftHalf); | ||
rightHalf = sortList(rightHalf); | ||
head = merge(leftHalf, rightHalf); | ||
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return head; | ||
} | ||
}; |