typos

src/algebra/continued-fractions.md

@@ -610,10 +610,10 @@ Another important concept for continued fractions are the so-called [linear frac
 
     Moreover, for $x=[a_{k+1}; \dots, a_n]$ it is equal to $L(A)$. Hence, $b_0 = \lfloor L(A) \rfloor$ is between $\lfloor L(\frac{p_k}{q_k}) \rfloor$ and $\lfloor L(\frac{p_{k-1}}{q_{k-1}}) \rfloor$. When they're equal, they're also equal to $b_0$.
 
-    Note that $L(A) = (L_{b_0} \circ L_{b_1} \circ \dots \circ L_{b_m})(\infty)$. Knowing $b_0$, we can compute compose $L_{b_0}^{-1}$ with the current transform and continue adding $L_{a_{k+1}}$, $L_{a_{k+2}}$ and so on, looking for new floors to agree, from which we would be able to deduce $b_1$ and so on until we recover all values of $[b_0; b_1, \dots, b_m]$.
+    Note that $L(A) = (L_{b_0} \circ L_{b_1} \circ \dots \circ L_{b_m})(\infty)$. Knowing $b_0$, we can compose $L_{b_0}^{-1}$ with the current transform and continue adding $L_{a_{k+1}}$, $L_{a_{k+2}}$ and so on, looking for new floors to agree, from which we would be able to deduce $b_1$ and so on until we recover all values of $[b_0; b_1, \dots, b_m]$.
 
 !!! example "Continued fraction arithmetics"
-    Let $A=[a_0; a_1, \dots, a_n]$ and $B=[b_0; b_1, \dots, b_m]$. Compose the continued fraction representations of $A+B$ and $A \cdot B$.
+    Let $A=[a_0; a_1, \dots, a_n]$ and $B=[b_0; b_1, \dots, b_m]$. Compute the continued fraction representations of $A+B$ and $A \cdot B$.
 ??? hint "Solution"
     Idea here is similar to the previous problem, but instead of $L(x) = \frac{ax+b}{cx+d}$ you should consider bilinear fractional transform $L(x, y) = \frac{axy+bx+cy+d}{exy+fx+gy+h}$.