Fix r.html.next() for next url

kzmaker · Sep 19, 2018 · 3d6b828 · 3d6b828
1 parent 69bc5dc
commit 3d6b828
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Showing 2 changed files with 5 additions and 5 deletions.
diff --git a/requests_html.py b/requests_html.py
@@ -430,7 +430,7 @@ def __init__(self, *, session: Union['HTMLSession', 'AsyncHTMLSession'] = None,
     def __repr__(self) -> str:
         return f"<HTML url={self.url!r}>"
 
-    def _next(self, fetch: bool = False, next_symbol: _NextSymbol = DEFAULT_NEXT_SYMBOL) -> _Next:
+    def next(self, fetch: bool = False, next_symbol: _NextSymbol = DEFAULT_NEXT_SYMBOL) -> _Next:
         """Attempts to find the next page, if there is one. If ``fetch``
         is ``True`` (default), returns :class:`HTML <HTML>` object of
         next page. If ``fetch`` is ``False``, simply returns the next URL.
@@ -478,19 +478,19 @@ def __iter__(self):
         while True:
             yield next
             try:
-                next = next._next(fetch=True, next_symbol=self.next_symbol).html
+                next = next.next(fetch=True, next_symbol=self.next_symbol).html
             except AttributeError:
                 break
 
     def __next__(self):
-        return self._next(fetch=True, next_symbol=self.next_symbol).html
+        return self.next(fetch=True, next_symbol=self.next_symbol).html
 
     def __aiter__(self):
         return self
 
     async def __anext__(self):
         while True:
-            url = self._next(fetch=False, next_symbol=self.next_symbol)
+            url = self.next(fetch=False, next_symbol=self.next_symbol)
             if not url:
                 break
             response = await self.session.get(url)

diff --git a/tests/test_internet.py b/tests/test_internet.py
@@ -18,7 +18,7 @@ def test_pagination():
 
 
 @pytest.mark.asyncio
-async def test_pagination(event_loop):
+async def test_async_pagination(event_loop):
     asession = AsyncHTMLSession()
     pages = (
         'https://xkcd.com/1957/',