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Evaluate division
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Tushar Roy committed Nov 1, 2016
1 parent 7bd7992 commit 4d3589b
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87 changes: 87 additions & 0 deletions src/com/interview/graph/EvaluateDivison.java
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package com.interview.graph;

import java.util.HashMap;
import java.util.Map;

/**
* Date 10/31/2016
* @author Tushar Roy
*
* Equations are given in the format A / B = k, where A and B are variables represented as strings, and k is a real number (floating point number).
* Given some queries, return the answers. If the answer does not exist, return -1.0.
*
* Solution
* Do Flyod warshall algorithm initialized as values between equations. Do Flyod Warshall to create
* all possible paths b/w two strings.
*
* Time complexity O(n * n * n) + O(m)
* where n is total number of strings in equations and m is total number of queries
*
* Reference
* https://leetcode.com/problems/evaluate-division/
*/
public class EvaluateDivison {
public double[] calcEquation(String[][] equations, double[] values, String[][] queries) {
if (equations.length == 0) {
return new double[0];
}
Map<String, Integer> index = new HashMap<>();
int count = 0;
for (int i = 0; i < equations.length; i++) {
String first = equations[i][0];
String second = equations[i][1];
if (!index.containsKey(first)) {
index.put(first, count++);
}
if (!index.containsKey(second)) {
index.put(second, count++);
}
}

double graph[][] = new double[count][count];
for (int i = 0; i < graph.length; i++) {
for (int j = 0; j < graph[i].length; j++) {
graph[i][j] = -1;
}
}

for (int i = 0; i < equations.length; i++) {
String first = equations[i][0];
String second = equations[i][1];
int i1 = index.get(first);
int i2 = index.get(second);
graph[i1][i1] = graph[i2][i2] = 1.0;
graph[i1][i2] = values[i];
graph[i2][i1] = 1/values[i];
}

for (int i = 0 ; i < graph.length; i++) {
for (int j = 0; j < graph.length; j++) {
if (graph[i][j] != -1) {
continue;
}
for (int k = 0; k < graph.length; k++) {
if (graph[i][k] == -1 || graph[k][j] == -1) {
continue;
}
graph[i][j] = graph[i][k] * graph[k][j];
}
}
}

double[] result = new double[queries.length];
for (int i = 0; i < queries.length; i++) {
String first = queries[i][0];
String second = queries[i][1];
if (!index.containsKey(first) || !index.containsKey(second)) {
result[i] = -1;
} else {
int i1 = index.get(first);
int i2 = index.get(second);
result[i] = graph[i1][i2];
}
}

return result;
}
}

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