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// Source : https://oj.leetcode.com/problems/remove-duplicates-from-sorted-array/ | ||
// Author : [email protected] | ||
// Date : 2014-10-24 | ||
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/*********************************************************************************************** | ||
* | ||
* Given a sorted array, remove the duplicates in place such that each element appear | ||
* only once and return the new length. | ||
* | ||
* Do not allocate extra space for another array, you must do this in place with constant memory. | ||
* | ||
* For example, | ||
* Given input array A = [1,1,2], | ||
* | ||
* Your function should return length = 2, and A is now [1,2]. | ||
* | ||
***********************************************************************************************/ | ||
class Solution { | ||
public: | ||
int removeDuplicates(int A[], int n) { | ||
int flag=0; | ||
if(n==0) return 0;//这里一定要注意n=0的情况 | ||
for(int i=1; i<n; i++) { | ||
if(A[i]!=A[flag]) { | ||
A[++flag]=A[i]; | ||
} | ||
} | ||
return flag+1; | ||
} | ||
}; |