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Correct misspelling of Chebyshev
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Michael Norrish committed Jun 12, 2020
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Expand Up @@ -1134,7 +1134,7 @@ $(S_n - \mathscr{E}(S_n))/n$ converges to 0, in probability
(weak law) or almost everywhere (strong law).

For uncorrelated r.v.'s with a common bound of variance, the proof is
simple and based on Markov and Chebeshev's inequalities. The centered
simple and based on Markov's and Chebyshev's inequalities. The centered
average actually converges to 0 in $L^2$, thus also in
probability~\cite[108]{Chung:2001}.
Under the same hypotheses it also converges to 0 almost everywhere:
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